Special Permutations

给定一个长度为$m$的序列$x$ 记： >排列$p_i(n)=[i,1,2,...,i-1,i+1,...,n]$ >$pos(p,x)$表示$x$在排列$p$中的第几位 >$f(p)=\sum_{i=1}^{m-1}|pos(p,x_i)-pos(p,x_{i+1})|$ 求$f(p_1(n)),f(p_2(n)),...,f(p_n(n))$。 $2\le n,m\le2\times10^5,1\le x_i\le n$

Let's define $ p_i(n) $ as the following permutation: $ [i, 1, 2, \dots, i - 1, i + 1, \dots, n] $ . This means that the $ i $ -th permutation is almost identity (i.e. which maps every element to itself) permutation but the element $ i $ is on the first position. Examples: - $ p_1(4) = [1, 2, 3, 4] $ ; - $ p_2(4) = [2, 1, 3, 4] $ ; - $ p_3(4) = [3, 1, 2, 4] $ ; - $ p_4(4) = [4, 1, 2, 3] $ . You are given an array $ x_1, x_2, \dots, x_m $ ( $ 1 \le x_i \le n $ ). Let $ pos(p, val) $ be the position of the element $ val $ in $ p $ . So, $ pos(p_1(4), 3) = 3, pos(p_2(4), 2) = 1, pos(p_4(4), 4) = 1 $ . Let's define a function $ f(p) = \sum\limits_{i=1}^{m - 1} |pos(p, x_i) - pos(p, x_{i + 1})| $ , where $ |val| $ is the absolute value of $ val $ . This function means the sum of distances between adjacent elements of $ x $ in $ p $ . Your task is to calculate $ f(p_1(n)), f(p_2(n)), \dots, f(p_n(n)) $ .

The first line of the input contains two integers $ n $ and $ m $ ( $ 2 \le n, m \le 2 \cdot 10^5 $ ) — the number of elements in each permutation and the number of elements in $ x $ . The second line of the input contains $ m $ integers ( $ m $ , not $ n $ ) $ x_1, x_2, \dots, x_m $ ( $ 1 \le x_i \le n $ ), where $ x_i $ is the $ i $ -th element of $ x $ . Elements of $ x $ can repeat and appear in arbitrary order.

Print $ n $ integers: $ f(p_1(n)), f(p_2(n)), \dots, f(p_n(n)) $ .

4 4
1 2 3 4

3 4 6 5 

5 5
2 1 5 3 5

9 8 12 6 8 

2 10
1 2 1 1 2 2 2 2 2 2

3 3 

Consider the first example: $ x = [1, 2, 3, 4] $ , so - for the permutation $ p_1(4) = [1, 2, 3, 4] $ the answer is $ |1 - 2| + |2 - 3| + |3 - 4| = 3 $ ; - for the permutation $ p_2(4) = [2, 1, 3, 4] $ the answer is $ |2 - 1| + |1 - 3| + |3 - 4| = 4 $ ; - for the permutation $ p_3(4) = [3, 1, 2, 4] $ the answer is $ |2 - 3| + |3 - 1| + |1 - 4| = 6 $ ; - for the permutation $ p_4(4) = [4, 1, 2, 3] $ the answer is $ |2 - 3| + |3 - 4| + |4 - 1| = 5 $ . Consider the second example: $ x = [2, 1, 5, 3, 5] $ , so - for the permutation $ p_1(5) = [1, 2, 3, 4, 5] $ the answer is $ |2 - 1| + |1 - 5| + |5 - 3| + |3 - 5| = 9 $ ; - for the permutation $ p_2(5) = [2, 1, 3, 4, 5] $ the answer is $ |1 - 2| + |2 - 5| + |5 - 3| + |3 - 5| = 8 $ ; - for the permutation $ p_3(5) = [3, 1, 2, 4, 5] $ the answer is $ |3 - 2| + |2 - 5| + |5 - 1| + |1 - 5| = 12 $ ; - for the permutation $ p_4(5) = [4, 1, 2, 3, 5] $ the answer is $ |3 - 2| + |2 - 5| + |5 - 4| + |4 - 5| = 6 $ ; - for the permutation $ p_5(5) = [5, 1, 2, 3, 4] $ the answer is $ |3 - 2| + |2 - 1| + |1 - 4| + |4 - 1| = 8 $ .